Give the Reaction for formation of Chloretone

Answer

### Step-by-Step Text Solution for the Formation of Chloretone

1. **Identify the Reactants**:
Chloretone is formed from two reactants: chloroform (CHCl₃) and acetone (CH₃COCH₃).

2. **Write the Chemical Equation**:
The reaction can be represented as:
\[ \text{CH}_3\text{COCH}_3 + \text{CHCl}_3 \xrightarrow{\text{Base}} \text{Chloretone} \]

3. **Role of the Base**:
A strong base is required for the reaction. The base abstracts an acidic hydrogen from acetone. The acidic hydrogen is the one attached to the carbon adjacent to the carbonyl group (C=O) in acetone.

4. **Formation of a Carbanion**:
When the base abstracts the acidic hydrogen from acetone, it forms a carbanion. The structure of the carbanion can be represented as:
\[ \text{CH}_3\text{C}^-\text{OCH}_3 \]
The negative charge is stabilized by the three electronegative chlorine atoms in chloroform.

5. **Nucleophilic Attack**:
The carbanion (nucleophile) then attacks the carbon of the chloroform (electrophile), which is partially positive due to the presence of chlorine atoms. This leads to the formation of a new bond.

6. **Formation of Chloretone**:
The product formed is chloretone (CH₃COCHCl₃). The reaction can be summarized as:
\[ \text{CH}_3\text{C}^-\text{OCH}_3 + \text{CHCl}_3 \rightarrow \text{CH}_3\text{C(OH)}\text{CCl}_3 \]

7. **Protonation**:
Finally, the negatively charged oxygen in the intermediate product can pick up a proton (H⁺) from the solution, resulting in the final product:
\[ \text{Chloretone: CH}_3\text{C(OH)}\text{CCl}_3 \]

### Final Reaction
The overall reaction for the formation of chloretone can be summarized as:
\[ \text{CH}_3\text{COCH}_3 + \text{CHCl}_3 \xrightarrow{\text{Base}} \text{CH}_3\text{C(OH)}\text{CCl}_3 \]

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