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Zn+CU^(2)(aq) Cu+Zn^(2)(aq) Reaction is ...

`Zn+CU^(2)(aq)` `Cu+Zn^(2)(aq)` Reaction is `Q= ([AN^(2+)])/([CU^(2+)])` . Variation of `E_(cell)` with log Q is of the type with QA = 1.10V. `E_(cell)` will be `1.1591V` when.

A

`[Cu^(2+)]//[Zn^(2+)]=0.01`

B

`[Zn^(2+)]//[Cu^(2+)]=0.01`

C

`[Zn^(2+)]//[Cu^(2+)]=0.1`

D

`[Zn^(2+)]//[Cu^(2+)]=1`

Text Solution

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The correct Answer is:
B
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