A cell Ag|`Ag^+||Cu^(++)|Cu` initially contains `2M Ag^+` and `2M Cu^(++)` ions. The change in cell potential after the passage of 10 amp current for 4825 sec is:

Options

A. `-0.00738V`
B. `-1.00738V`
C. `-0.0038V`
D. none

Answer

A

Explanation

`Q=10xx4825=48250C`
no. of faraday `=(48250)/(96500)=0.5`
`Ag+undersetunderset(2-0.25)(2.00)((1)/(2)Cu^(++))toundersetunderset(2+0.50)(2.00)(Ag^(+))+(1)/(2)Cu`
`E_(cell)=E_(cell)^(@)-(0.0591)/(1)log(([Ag^(+)])/([Cu^(++)]^(1//2)))`
`E_(1)=E_(cell)^(@)-(0.0591)/(1)log((2.00)/((2.00)^(1/2)))`
`E_(2)=E_(cell)^(@)-(0.0591)/(1)log((2.50)/((1.75)^(1//2)))`
`triangleE=E_(2)-E_(1)=(0.0591)/(1)[logsqrt(2)-log((2.50)/(sqrt(1.75)))]=(0.0591)/(1)[log1.41-log1.88]`
`=(0.0591)/(1)[0.1492-0.2742]=-(0.0591)/(1)xx0.125=-0.00738V`.