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With t taken is seconds and I taken in A...

With t taken is seconds and I taken in Amp. The variation of I follows the equation `t^(2)+I^(2)=25`
what amount of Ag will be electrode posited with this current flowing in the interval 0-5 second ? (Ag GAM or Ag=108)

A

22 mg

B

66 mg

C

77 mg

D

88 mg

Text Solution

Verified by Experts

The correct Answer is:
A

`Q=(pi(25))/(4)C=(pixx25)/(4xx96500)F`
`thereforem=(108)/(1)xx(pixx25)/(4xx96500)g=0.02197g=21.97mg~=mg`
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