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The molar conductivities, ^^(NaOAc)^(oo)...

The molar conductivities, `^^_(NaOAc)^(oo)` and `^^_(HCI)^(@)` at infinite dilution in water at `25^(@)C` are `91.0` and `426.2 S cm^(2)//mol` respectively. To calculate `^^_(HOAc)^(@)` the additional value required is:

A

`^^_(H_(2)O)^(0)`

B

`^^_(KCl)^(0)`

C

`^^_(NaOH)^(0)`

D

`^^_(NaCl)^(0)`

Text Solution

Verified by Experts

The correct Answer is:
D
`CH_(3)COONa+HCltoCH_(3)COOH+NaCl`" From the reaction"`
`overset(0)^^CH_(3)COONa+overset(0)(^^)_(HCl)=overset(0)(^^)_(CH_(3))COOH+overset(0)(^^)_(NaCl)oroverset(0)(^^)_(CH_(3)COOH)=overset(0)(^^)_(CH_(3)COONa)+overset(0)(^^)_(HCl)-overset(0)(^^)_(NaCl)`
Thus to calculate the value of `overset(0)(^^)CH_(3)COOH` one should know know the value of `overset(0)(^^)_(NaCl)` along with `overset(0)(^^)_(CH_(3)COONa)` and `overset(0)(^^)_(HCl^(-))`
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RESONANCE ENGLISH-ELECTROCHEMISRY-Part 2
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  14. The cell : (Zn|Zn^(2+)(1M)|| Cu^(2+)(1M)|Cu) (E(cell)^(@)= 1.10V),wa...

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  15. Given: E(Cr^(3+)//Cr)^(@) =- 0.72 V, E(Fe^(2+)//Fe)^(@) =- 0.42V. The ...

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  16. Given : E(Fe^(3+)//Fe)^(@) = -0.036V, E(FE^(2+)//Fe)^(@)= -0.439V. The...

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