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Given the data at 25^(@)C, Ag((s)) +I(...

Given the data at `25^(@)C`,
`Ag_((s)) +I_((aq))^(-) rarr AgI_((s)) +e^(-), E^(@) = 0.152V`
`Ag_((s)) rarr Ag_((aq))^(+) +e^(-), E^(@) =- 0.800V`
what is the value of log `K_(sp)` for `AgI`?
(Where `K_(sp)=` solubility product)
`(2.303(RT)/(F) =0.059V)`

A

`-8.12`

B

`+8.612`

C

`-37.83`

D

`-16.13`

Text Solution

Verified by Experts

The correct Answer is:
D
`0.152=-0.8-(0.059)/(1)logK_(SP):logK_(SP)=-16.11`
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Given the data 25^(@) C , Ag+ I^(-) to AgI+e^(-) , E^(@) = 0.152V Ag to Ag^(+) + E(-) , E^(@) = - 0.800V What is the value of K_(sp) for AgI?

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