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The cell : (Zn|Zn^(2+)(1M)|| Cu^(2+)(1M)...

The cell : `(Zn|Zn^(2+)(1M)|| Cu^(2+)(1M)|Cu)`
`(E_(cell)^(@)= 1.10V)`,was allowed to be discharged bu 50% ar 298k . The relative conentration of `Zn^(2+) to Cu^(2+) (([Zn^(2+)])/([Cu^(2+)]))` is :

A

`10^(37.3)`

B

`9.65xx10^(4)`

C

antilog `(24.08)`

D

`37.3`

Text Solution

Verified by Experts

The correct Answer is:
A
`0=+1.1-(0.0591)/(6)log(([Cr^(+3)])/([Cu^(2+)])),log(([Zn^(2+)])/[[Cu^(2+)]))=37.3,(([Zn^(2+)])/([Cu^(2+)]))=10^(37.3)`
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