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Given : E(Fe^(3+)//Fe)^(@) = -0.036V, E(...

Given : `E_(Fe^(3+)//Fe)^(@) = -0.036V, E_(FE^(2+)//Fe)^(@)= -0.439V`. The value of electrode potential for the change, `Fe_(aq)^(3+) + e^(-)rightarrow Fe^(2+) (aq)` will be :

A

0.385 V

B

0.770 V

C

`-0.270 V`

D

`-0.072`

Text Solution

Verified by Experts

The correct Answer is:
B
`Fe^(3+)+3e^(-)toFe" "triangleG_(1)=-3xxFxxF_(Fe^(3+)//Fe)^(0)`
`Fe^(2+)toFe" "triangleG_(2)=-2xxFxxE_(Fe^(2+)//Fe)^(0)`
`Fe^(3+)+e^(-)toFe^(2+)" "triangleG=triangleG_(1)-triangleG_(2)`
`triangleG=3xx0.036F-2xx0.439xxF=-1xxE_((Fe^(3+)//Fe^(+2)))^(0)xxF`
`E_((Fe^(3+)//Fe^(+2)))^(0)=2xx0.439-3xx0.036`
`=0.878-0.108`
`=0.770V`
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