The ester ethyl acetate is formed by the reaction of ethanol and acetic acid and the equilibrium is represented as
`CH_3COOH (l) + C_2H_5OH(l) hArr CH_3COOC_2H_5(l) +H_2O (l)`
Write the concentration ratio , Q for this reaction. Note that water is not in excess and is not a solvent in this reactions .

Answer

(i) `Q_(C)=([CH_(3)COOC_(2)H_(5)][H_(2)O])/([CH_(3)COOH][C_(2)H_(5)OH])` (ii) `K_(c)3.5` (iii) `"AS"Q_(c)=K_(c)`, equilibrium has not been attained.

Explanation

(i) `Q_(c)=([CH_(3)COOC_(2)H_(5)][H_(2)O])/([CH_(3)COOH][C_(2)H_(5)OH])`
(ii) `CH_(3)COOH+C_(2)H_(5)OHhArrCH_(3)COOC_(2)+H_(2)O`
(ii) `{:(Initial,1.00mol,0.180mol,,,),("At eqm".,1-0.17,0.180-0.17,0.17,0.17,):}`
`K_(c)=([CH_(3)COOC_(2)H_(5)][H_(2)O])/([CH_(3)COOH][C_(2)H_(5)OH])=(0.17xx0.17)/(0.83xx0.01)=(1)/(6)`
(iii) `CH_(3)COOH+C_(2)H_(5)OHhArrCH_(3)COOc_(2)H_(5)+H_(2)O`
`{:(Initial,1.000mol,0.500mol,,,),(After,1-0.214,0.500-0.214,0.214mol,0.214mol,):}`
Reaction quotient `(Q_(c))=((0.214//V)(0.214//V))/((0.786//V//)(0.286//V))=0.204`
As `Q_(c)=K_(c)`,equilibrium has not been attained.