Solid Ammonium carbamate dissociates as:
`NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g).`
In a closed vessel, solid ammonium carbamate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of `NH_(3)` at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure.

Answer

58

Explanation

`NH_(2)COONH_(4)(s)hArr2NH_(2)(g)+CO_(2)(g)`
`2P_(@) P_(@) K_(P)=(2P_(@))^(2)xxP_(@)=4P_(@)^(2)`
`3P_(@) P' K_(P)=(3P_(@))^(2)xxP=9P_(@)^(2).P`
`P=(4)/(9)P_(@)`
`(P^(t))/(P^(t))=(3P_(@)+(4)/(9)P_(@))/(3P_(@))=(31)/(27)`