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CaCO(3)(s)hArrCaO(s)+CO(2)(g) CO(2)(g)...

`CaCO_(3)(s)hArrCaO(s)+CO_(2)(g)`
`CO_(2)(g)hArrCO(g)+(1)/(2)O_(2)(g)`
For above simultaneous equilibrium if `CO_(2)` is added from out side at equilibrium then:

A

`P_(CO_(2)` will increase

B

`P_(CO_(2)` will decrease

C

No shift in `2^(nd)` equilibrium

D

Backward shift in `1^(st)` equilibrium

Text Solution

Verified by Experts

The correct Answer is:
C, D
Second equilibrium will not be affected by `CO_(2)` addition only first will shift backward.
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