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AB(s)hArrA(g)+B(g)K(p)=4,DeltaH=+ve In...

`AB(s)hArrA(g)+B(g)K_(p)=4,DeltaH=+ve`
In a container,`A`(g) "and" B(g) are filled to partial pressure of `1` atm each. Now `AB(s)` is added (in excess quantity). Which of the following is CORRECT? (No other gas is present in container):

A

At equilibrium, the total pressure in the container is `4` atm.

B

Equilibrium pressure decreases uniformly on increasing the volume by container.

C

At equilibrium, the total pressure in the container is more than `4` atm, if temperature is increased.

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the equilibrium reaction given and the conditions provided. ### Step 1: Understand the Reaction The reaction is given as: \[ AB(s) \rightleftharpoons A(g) + B(g) \] with \( K_p = 4 \) and \( \Delta H = +ve \) (indicating that the reaction is endothermic). ### Step 2: Initial Conditions Initially, the partial pressures of gases \( A \) and \( B \) are both 1 atm: - \( P_A = 1 \, \text{atm} \) - \( P_B = 1 \, \text{atm} \) ### Step 3: Calculate Initial Reaction Quotient (Q) The reaction quotient \( Q \) is calculated as: \[ Q = P_A \times P_B = 1 \times 1 = 1 \, \text{atm}^2 \] ### Step 4: Compare Q and Kp Since \( K_p = 4 \) and \( Q = 1 \): - \( Q < K_p \) This means that the reaction will shift to the right to reach equilibrium, producing more \( A \) and \( B \). ### Step 5: Change in Partial Pressures Let \( x \) be the change in the partial pressures of \( A \) and \( B \) at equilibrium. Thus: - \( P_A = 1 + x \) - \( P_B = 1 + x \) ### Step 6: Write the Expression for Kp At equilibrium, the expression for \( K_p \) is: \[ K_p = (P_A)(P_B) = (1 + x)(1 + x) = 4 \] Expanding this gives: \[ (1 + x)^2 = 4 \] Taking the square root: \[ 1 + x = 2 \] Thus: \[ x = 1 \] ### Step 7: Calculate Equilibrium Partial Pressures Now we can find the equilibrium partial pressures: - \( P_A = 1 + 1 = 2 \, \text{atm} \) - \( P_B = 1 + 1 = 2 \, \text{atm} \) ### Step 8: Calculate Total Pressure at Equilibrium The total pressure \( P_{total} \) at equilibrium is: \[ P_{total} = P_A + P_B = 2 + 2 = 4 \, \text{atm} \] ### Step 9: Analyze the Options 1. **Option 1**: At equilibrium, the total pressure in the container is 4 atm. **(Correct)** 2. **Option 2**: Equilibrium pressure decreases uniformly on increasing the volume of the container. **(Correct)** 3. **Option 3**: At equilibrium, the total pressure in the container is more than 4 atm if the temperature is increased. **(Correct)** 4. **Option 4**: None of these. **(Incorrect)** ### Conclusion All three options 1, 2, and 3 are correct based on the analysis of the equilibrium conditions. ---
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