Home
Class 11
CHEMISTRY
CuSO(4).5H(2)O(s)hArrCuSO(4).3H(2)O(s)+2...

`CuSO_(4).5H_(2)O(s)hArrCuSO_(4).3H_(2)O(s)+2H_(2)O(s) K_(P)=0.4xx10^(-3) atm^(2)`
Which of following sttement are correct:

A

`DeltaG^(@)=-RTlnP_(H_(2)O)` where `P_(H_(2)O)="partial pressure of" H_(2)O` at equilibrium.

B

At vapour pressure of `H_(2)O=15.2` torr relative humidity of `CuSO_(4).5H_(2)O "is"100%`

C

In pressure of aqueous tension of `24` torr, `CuSO_(4).5H_(2)O` can not loss moisture.

D

In presence of dry atmosphere in open container `CuSO_(4).5H_(2)O` will completely convert into `CuSO_(4).3H_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
(A) `K_(p)=(P_(H_(2)O))^(2)`
`=0.4xx10^(-3)=4xx10^(-4)atm^(2)`
`(P_(H_(2^O)))_(equi)=2xx10^(-2)atm`
`=2xx10^(-2)atm`
`=2xx10^(-2)xx760=15.2` torr
(B) Relative humidity`=(15.2)/(15.2)xx100=100%`(IfV.P.`=15.2` torr)
(C) When `P_(H_(2)O)gt(P_(H_(2)O))_(equi)` backward shift so at `24` torr pressure reaction shift backward.
(D) In dry atmosphere and open container reaction shift completely in forward.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Advanced Level Problems (Part-2)(Section-3)|6 Videos

  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Advanced Level Problems (Part-3)(Stage-1)|38 Videos

  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Advanced Level Problems (Part-2)(Section-1)|7 Videos

  • CHEMICAL BONDING

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Fundamental Concept )|6 Videos

  • D & F-BLOCK ELEMENTS & THEIR IMPORTANT COMPOUNDS

    RESONANCE ENGLISH|Exercise Match the column|1 Videos

Similar Questions

Explore conceptually related problems

CuSO_(4).5H_(2)O(s)hArrCuSO_(4). 3H_(2)O(s)+2H_(2)O(g), K_(p)=4xx10^(-4)atm^(2) If the vapour pressure of water is 38 toor then percentage of relatative humidity is :(Assume all data at constant temperture)

Under what pressure conditions CuSO_(4).5H_(2)O be efforescent at 25^(@)C . How good a drying agent is CuSO_(4).3H_(2)O at the same temperature? Given CuSO_(4).5H_(2)O(s) hArr CuSO_(4).3H_(2)O(s)+2H_(2)O(v) K_(p)=1.086xx10^(-4) atm^(2) at 25^(@)C . Vapour pressure of water at 25^(@)C is 23.8 mm of Hg.

CuSO_(4) .5H_(2)O_((g)) hArr CuSO_(4), 3H_(2)O_((s)) + 2H_(2) O_((g)) , K_(p) = 4 xx 10^(-4) atm^(2) . If the vapour pressure of wateris 38 torr then percentage of relative humidity is: (Assume all data at constant temperature)

For the equilibrium CuSO_(4)xx5H_(2)O(s)hArrCuSO_(4)xx3H_(2)O(s) + 2H_(2)O(g) K_(p) = 2.25xx10^(-4)atm^(2) and vapour pressure of water is 22.8 torr at 298 K. CuSO_(4) . 5H_(2)O(s) is efflorescent (i.e., losses water) when relative humidity is :

In CuSO_(4) · 5H_(2)O

For equilibrium ZnSO_(4).7H_(2)O(s)hArrZnSO_(4).2H_(2)O(s)+5H_(2)O(g) K_(P)=56.25xx10^(-10) atm^(5) and vapour pressure of water is 22.8 torr at 298K.ZnSO_(4).7H_(2)O(s) is efflorescent (lose water) when relative humidity is [5sqrt56.25=2.23]

Na_(2)SO_(4).10H_(2)O(s)hArrNa_(2)SO_(4).5H_(2)O(g) K_(P)=2.43xx10^(-8) atm^(5) incorrect statement is-

(a) CuSO_(4).5H_(2)O(s)hArrCuSO_(4).3H_(2)O(s)+2H_(2)O(g) K_(p)=4xx10^(-4)atm^(2) (b) Na_(2)SO_(4).10H_(2)O(s)hArrNa_(2)SO_(4).5H_(2)O(s)+5H_(2)O(g) K_(p)=2.43xx10^(-8) atm^(5) (c) Na_(2)S_(2)O_(3).5H_(2)O(s)hArrNa_(2)S_(2)O_(3).2H_(2)O(s)+3H_(2)O(g) K_(p)=6.4xx10^(-5) atm^(3) What is order of vapour pressure and relative humidity respectively.

For the reaction CuSO_(4).5H_(2)O(s) hArr CuSO_(4).3H_(2)O(s)+2H_(2)O(g) Which one is the correct representation?

CuSO_(4),5H_(2)O(s)hArrCuSO_(4)(s)+5H_(2)O(g)K_(P)=10^(-10) "moles of" CuSO_(4).5H_(2)O(s) is taken in a 2.5L container at 27^(@)C then at equilibrium [Take: R=(1)/(12) litre atm mol^(-1)K^(-1) ]