An organic compound 'A' having molecular formula `C_(6)H_(6)O` gives a characteristic colour with aqueous `FeCl_(3)` solution. When 'A' is treated with `CO_(2)` and NaOH at 400K under pressure. 'B' is obtained. B on acidification gives C when C treated with `CH_(3)COCl` gives a popular pain killer D. Deduce the strucutrues of A,B,C and D.
Text Solution
AI Generated Solution
To deduce the structures of compounds A, B, C, and D, we will follow the clues provided in the question step by step.
### Step 1: Identify Compound A
The molecular formula of compound A is \(C_6H_6O\). Given that it gives a characteristic color with aqueous \(FeCl_3\), we can conclude that compound A is **phenol**.
**Structure of A:**
- **Phenol**: \(C_6H_5OH\)
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