The aniline reaction with…to..yield… as the final product..

Options

A. Aqueous bromine, 2-bromoaniline
B. Aqueous bromine, 2,46-tribromoaniline
C. chloroform/KOH, phenyl cyanide
D. acetyl chloride, benzanilide

Explanation

### Step-by-Step Solution:

1. **Identify the Reactant**: The reactant in this case is aniline, which has the formula C6H5NH2. It consists of a benzene ring (C6H5) attached to an amino group (NH2).

2. **Identify the Reagent**: The reagent we are considering is aqueous bromine (Br2 in water). Aqueous bromine is known to react with aniline due to the electron-donating nature of the amino group.

3. **Understand the Reaction Mechanism**: When aniline reacts with aqueous bromine, the amino group (NH2) donates electrons to the benzene ring, increasing the electron density at the ortho and para positions of the ring. This makes these positions more reactive towards electrophilic substitution.

4. **Substitution Reaction**: Since aqueous bromine is in excess, it will brominate all available positions at the ortho and para locations. The final product will have bromine atoms substituted at the 2, 4, and 6 positions of the benzene ring.

5. **Determine the Final Product**: The final product of this reaction is 2,4,6-tribromoaniline. The structure can be represented as follows:
- The benzene ring has bromine atoms at positions 2, 4, and 6.
- The amino group (NH2) remains attached at position 1.

6. **Conclusion**: Therefore, the reaction of aniline with aqueous bromine yields 2,4,6-tribromoaniline as the final product.

### Final Answer:
Aniline reacts with aqueous bromine to yield 2,4,6-tribromoaniline as the final product.

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