In how many of the following reactions, colored precipitate is obtained?
(a). `CuSO_(4)+NaoH("excess")to`, (b) `CuCl_(2)+NH_(3)("excess")to` ltBrgt (c) `ZnSO_(4)+NaOH("excess")to`
(d) `ZnSO_(4)+NH_(3)("excess")to` , (e) `FeSO_(4)+NaOH("excess")underset(air)overset("in")to` , (f) `FeCl_(3)+NaoH("Excess")to`
(g) `CuSO_(4)+Kl("excess")to`, (h) `ZnSO_(4)+NaHCO_(3)to`
(i) `CuCl_(2)+NaNO_(3)to`

Answer

To determine how many of the given reactions produce colored precipitates, we will analyze each reaction step by step.

### Step-by-Step Solution:

1. **Reaction (a): `CuSO4 + NaOH (excess)`**
- When copper sulfate reacts with sodium hydroxide, it forms a blue precipitate of copper(II) hydroxide, `Cu(OH)2`.
- **Result**: Colored precipitate (blue).

2. **Reaction (b): `CuCl2 + NH3 (excess)`**
- Copper(II) chloride reacts with excess ammonia to form a complex ion, tetraamine copper(II) chloride, which remains in solution.
- **Result**: No colored precipitate.

3. **Reaction (c): `ZnSO4 + NaOH (excess)`**
- Zinc sulfate reacts with sodium hydroxide to form a white precipitate of zinc hydroxide, `Zn(OH)2`.
- **Result**: Colored precipitate (white, but not colored in the sense of vivid colors).

4. **Reaction (d): `ZnSO4 + NH3 (excess)`**
- Zinc sulfate reacts with excess ammonia to form a complex ion, tetraamine zinc sulfate, which remains in solution.
- **Result**: No colored precipitate.

5. **Reaction (e): `FeSO4 + NaOH (excess) (in air)`**
- Iron(II) sulfate reacts with sodium hydroxide in the presence of air to form a green precipitate of iron(II) hydroxide, `Fe(OH)2`.
- **Result**: Colored precipitate (green).

6. **Reaction (f): `FeCl3 + NaOH (excess)`**
- Ferric chloride reacts with sodium hydroxide to form a brown precipitate of ferric hydroxide, `Fe(OH)3`.
- **Result**: Colored precipitate (brown).

7. **Reaction (g): `CuSO4 + KI (excess)`**
- Copper sulfate reacts with potassium iodide to form copper(I) iodide, `CuI`, which is a white precipitate, along with iodine.
- **Result**: Colored precipitate (white, but not vivid).

8. **Reaction (h): `ZnSO4 + NaHCO3`**
- Zinc sulfate reacts with sodium bicarbonate to form zinc carbonate, which is a white precipitate, along with sodium sulfate, water, and carbon dioxide.
- **Result**: Colored precipitate (white, but not vivid).

9. **Reaction (i): `CuCl2 + NaNO3`**
- Copper(II) chloride reacts with sodium nitrate to form copper(II) nitrate, which remains in solution.
- **Result**: No colored precipitate.

### Summary of Results:
- Reactions with colored precipitates:
- (a) `CuSO4 + NaOH` (blue)
- (e) `FeSO4 + NaOH` (green)
- (f) `FeCl3 + NaOH` (brown)

- Total reactions with colored precipitates: **3**

### Final Answer:
**3 reactions produce colored precipitates.**