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The following carbocation rearranges to ...

The following carbocation rearranges to
`CH_(2)=underset(CH_(3))underset(|)C-overset(CH_(3))overset(|)C-overset(o+)CH-overset(CH_(3))overset(|)(CH)-CH_(3)`

A

`CH_(2)=underset(Ch_(3))underset(|)C-underset(underset(o+)CH_(2))underset(|)CH-overset(CH_(3))overset(|)CH-overset(CH_(3))overset(|)CH-CH_(3)`

B

`CH_(2)=underset(CH_(3))underset(|)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-underset(o+)overset(CH_(3))overset(|)C-CH_(3)`

C

`CH_(2)=underset(CH_(3))underset(|)C-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-overset(CH_(3))overset(|)CH-underset(H)underset(|)overset(o+)C-CH_(3)`

D

`CH_(3)=underset(CH_(3))underset(|)C-underset(CH_(3))underset(|)overset(o+)C-overset(CH_(3))overset(|)CH-overset(CH_(3))overset(|)CH-CH_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of rearranging the given carbocation, we will follow these steps: ### Step 1: Identify the Structure of the Given Carbocation The given carbocation can be represented as follows: ``` CH3 | CH2 = C - C^+ - C - CH3 | CH3 ``` Here, the positive charge is located on a secondary (2°) carbocation. **Hint:** Always start by sketching the structure of the carbocation to visualize the rearrangement. ### Step 2: Determine the Stability of the Carbocation The stability of carbocations is crucial for determining whether a rearrangement will occur. The order of stability is: - Tertiary (3°) > Secondary (2°) > Primary (1°) Since we have a secondary carbocation, it can rearrange to a more stable tertiary carbocation. **Hint:** Remember that carbocations prefer to rearrange to a more stable form. ### Step 3: Perform the Rearrangement To increase the stability, the secondary carbocation can rearrange to a tertiary carbocation. This can occur through a hydride shift or a methyl shift. In this case, a methyl shift is more favorable. 1. The methyl group from the adjacent carbon (C) can migrate to the positively charged carbon (C^+). 2. The positive charge will then shift to the carbon that originally had the methyl group. The new structure after the rearrangement will be: ``` CH3 | CH2 = C - C - C^+ - CH3 | CH3 ``` Now the positive charge is on a tertiary carbon. **Hint:** Look for the adjacent carbon atoms to see which groups can migrate to stabilize the carbocation. ### Step 4: Final Structure After the rearrangement, the final structure of the carbocation will be: ``` CH3 | CH2 = C - C^+ - CH3 | CH3 ``` This structure shows the positive charge now on a tertiary carbon, which is more stable than the original secondary carbocation. **Hint:** Always verify that the final structure has a more stable carbocation than the initial one. ### Conclusion The rearrangement of the given carbocation results in a more stable tertiary carbocation. The final structure is confirmed to be more stable due to the positive charge being on a tertiary carbon.
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CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH=CH-CH_(3)overset(H-Cl)(to) ?

The number of tertiary carbon atoms in the following^ structure is CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C )-CH_(2)-overset(CH_(3))overset(|)(C )H-CH_(3)

IUPAC nomenclature of CH_3-underset(CH_2-CH_3)underset(|)overset(CH_3)overset(|)C-CH=overset(CH_3)overset(|)C-CH_3 is

Monomer of [-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-]_(n) is

Write its IUPAC name CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-underset(CH_(2))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)

For the given reaction how many monochloro products are optically active ( all isomers ) : CH_(3)-underset(" "CH_(3))underset(|)overset(" "CH_(3))overset(|)(C)-CH_(2)-overset(" "CH_(3))overset(|)(CH)-CH_(3) overset(Br_(2)//hv)(rarr)

Given the IUPAC names of the following compounds: (i) CH_(3)CH_(2)CH_(2)underset(C_(2)H_(5))underset(|)overset(CH_(3))underset(|)(C )CH_(2)-overset(CH_(3))overset(|)(C )=CH_(2) (ii) CH_(3)-overset(CH_(3))overset(C )H-C-=CH (iii) C_(6)H_(5)-CH=CH-CH_(2)Cl CH_(3)CH-CH-CH_(2)Cl (iv) CH_(3)CH=CH-CH_(2)Br v CH_(2)=CH-overset(Cl)overset(|)(C )-CH=CH_(2) vi CH_(2)=CH-overset(CH_(2)CH_(3))underset(|)(C )H-underset(Cl)underset(|)(C )=CH_(2) vii. (CH_(3))_(3)C - CH=CH_(2)

The monomer of the polymer ~CH_(2)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C)~

RESONANCE ENGLISH-GENERAL ORGANIC CHEMISTRY II-Part-I : Only One Option Correct Type
  1. Select the most stable intermediates :

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  2. Which of the following is most stable carbocation?

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  3. The most stable carbocation is:

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  4. The following carbocation rearranges to CH(2)=underset(CH(3))underse...

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  5. Correct basic strength order is :

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  6. The order of basic strength of the given basic nitrogen atoms is :

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  7. In the labelled N-atoms which is correct basic strength order:

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  8. Choose the strongest base among the following:

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  9. Select the basic strength order of following molecules ?

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  10. Which is the weakest base among the followings ?

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  11. Write the order of K(a(1)) values of following acids :

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  12. The acid strength order is :

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  13. (X) (C(6)H(3)CIBrCOOH) are a dihalosubstituted benzoic acids. The stro...

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  14. The order of acidity of the H-atoms underlined in the following compou...

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  15. Most acidic hydrogen is present in

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  16. The correct orders are:

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  17. Observe the following sequence of reactions : Select the correct ...

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  18. Order of K(a) which can be predicted by following reaction is:

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  19. The gases produced in the following reactions are respectively I: CH...

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  20. Decreasing order of enol content of the following compounds in liquid ...

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