The gases produced in the following reactions are respectively
`I: CH_(3)NH_(2) + NH_(2)Br to `
`II: CH_(3)SO_(3)H + NaHCO_(3) to `
`III: CH_(3) -underset(O)underset(||)C -NH_(2)+NaH to`

Options

A. `NH_(3),NH_(3), CO_(2)`
B. `NH_(3), SO_(2), H_(2)`
C. `NH_(3), CO_(2), H_(2)`
D. `NH_(3), SO_(2), NH_(3)`

Answer

To solve the question regarding the gases produced in the given reactions, we will analyze each reaction step by step.

### Step 1: Analyzing Reaction I
**Reaction I:**
\[ \text{CH}_3\text{NH}_2 + \text{NH}_2\text{Br} \]

In this reaction, methylamine (\( \text{CH}_3\text{NH}_2 \)) reacts with bromamine (\( \text{NH}_2\text{Br} \)). The expected products of this reaction include ammonia (\( \text{NH}_3 \)) as a gas.

**Gas Produced:**
- Ammonia (\( \text{NH}_3 \))

### Step 2: Analyzing Reaction II
**Reaction II:**
\[ \text{CH}_3\text{SO}_3\text{H} + \text{NaHCO}_3 \]

In this reaction, methanesulfonic acid (\( \text{CH}_3\text{SO}_3\text{H} \)) reacts with sodium bicarbonate (\( \text{NaHCO}_3 \)). The reaction produces sodium methanesulfonate and releases carbon dioxide (\( \text{CO}_2 \)) and water.

**Gas Produced:**
- Carbon dioxide (\( \text{CO}_2 \))

### Step 3: Analyzing Reaction III
**Reaction III:**
\[ \text{CH}_3\text{C}(=O)\text{NH}_2 + \text{NaH} \]

Here, acetamide (\( \text{CH}_3\text{C}(=O)\text{NH}_2 \)) reacts with sodium hydride (\( \text{NaH} \)). This reaction leads to the formation of sodium acetate and liberates hydrogen gas (\( \text{H}_2 \)).

**Gas Produced:**
- Hydrogen (\( \text{H}_2 \))

### Summary of Gases Produced
From the analysis of the three reactions, we can summarize the gases produced as follows:
1. From Reaction I: Ammonia (\( \text{NH}_3 \))
2. From Reaction II: Carbon dioxide (\( \text{CO}_2 \))
3. From Reaction III: Hydrogen (\( \text{H}_2 \))

### Final Answer
The gases produced in the reactions are:
- I: Ammonia (\( \text{NH}_3 \))
- II: Carbon dioxide (\( \text{CO}_2 \))
- III: Hydrogen (\( \text{H}_2 \))