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Consider the acidity of the carboxylic a...

Consider the acidity of the carboxylic acids :
`(i) PHCOOH" "(ii) o-NO_(2)C_(6)H_(4)COOH" "(iii) p-NO_(2)C_(6)H_(4)COOH" "(iv) m-NO_(2)C_(6)H_(4)COOH`

A

`i gt ii gt iii gt iv`

B

`ii gt iii gt iv gt i`

C

`iii gt ii gt iv gt i`

D

`ii gt iv gt iii gt i`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the acidity of the given carboxylic acids, we need to analyze the effect of substituents on the acidity of the carboxylic acid group (-COOH). The presence of electron-withdrawing groups (EWGs) increases the acidity of carboxylic acids, and their position relative to the carboxylic acid group plays a crucial role in this effect. ### Step-by-Step Solution: 1. **Identify the Compounds**: We have four carboxylic acids to consider: - (i) Benzoic acid (PHCOOH) - (ii) o-Nitrobenzoic acid (o-NO₂C₆H₄COOH) - (iii) p-Nitrobenzoic acid (p-NO₂C₆H₄COOH) - (iv) m-Nitrobenzoic acid (m-NO₂C₆H₄COOH) 2. **Understand the Effect of Substituents**: - Electron-withdrawing groups (like -NO₂) increase acidity by stabilizing the negative charge on the carboxylate ion formed after deprotonation. - The ortho position (o-) has a stronger effect than the para position (p-), and the meta position (m-) has the least effect. 3. **Rank the Acidity**: - **o-NO₂C₆H₄COOH**: The nitro group is at the ortho position, which has the strongest electron-withdrawing effect, thus making this compound the most acidic. - **p-NO₂C₆H₄COOH**: The nitro group is at the para position, which has a strong electron-withdrawing effect but is less effective than the ortho position. - **m-NO₂C₆H₄COOH**: The nitro group is at the meta position, which has a weaker electron-withdrawing effect compared to ortho and para positions. - **PHCOOH**: Benzoic acid has no electron-withdrawing group and will be the least acidic among the four. 4. **Final Order of Acidity**: Based on the above analysis, the order of acidity from strongest to weakest is: - (ii) o-NO₂C₆H₄COOH > (iii) p-NO₂C₆H₄COOH > (iv) m-NO₂C₆H₄COOH > (i) PHCOOH ### Conclusion: The correct order of acidity for the given carboxylic acids is: **o-NO₂C₆H₄COOH > p-NO₂C₆H₄COOH > m-NO₂C₆H₄COOH > PHCOOH**
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Consider the acidity of the carboxylic acids: (1) PhCOOH (2) o-NO_(2) C_(6) H_(4) COOH (3) p-NO_(2) C_(6) H_(4) COOH (4) m-NO_(2) C_(6) H_(4) COOH Which of the following order is correct?

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