`C_(5)H_(10)O overset(H_(3)O^(o+))rarrB+C`, (B) and (C) both give +ve iodoform test. Compound (A) is :

Options

A. `CH_(3)-CH=CH-O-CH_(2)-CH_(3)`
B. `CH_(3)-underset(CH_(3))underset(|)overset(H)overset(|)(C)-O-CH=CH_(2)`
C. `CH_(3)-underset(CH_(2))underset("||")(C)-O-CH_(2)-CH_(3)`
D. None of these

Answer

To solve the question, we need to identify the compound (A) with the molecular formula C₅H₁₀O that, upon hydrolysis, yields compounds (B) and (C) which both give a positive iodoform test.

### Step-by-Step Solution:

1. **Understanding the Iodoform Test**:
The iodoform test is a qualitative test for the presence of a methyl ketone or a secondary alcohol that can be oxidized to a methyl ketone. The positive result is indicated by the formation of a yellow precipitate of iodoform (CHI₃). The functional groups that can give a positive iodoform test include:
- Methyl ketones (RCOCH₃)
- Secondary alcohols that can be oxidized to methyl ketones (RCHOH)

2. **Analyzing the Molecular Formula**:
The compound (A) has the formula C₅H₁₀O. This suggests it could be a ketone, aldehyde, or alcohol.

3. **Considering Possible Structures**:
We can consider different structural possibilities for C₅H₁₀O:
- It could be a straight-chain alcohol, a branched alcohol, or a ketone.
- For example, it could be pentan-2-one, 3-pentanol, or 2-pentanol.

4. **Performing Hydrolysis**:
Hydrolysis of compound (A) will yield compounds (B) and (C). We need to find structures for (B) and (C) that both give a positive iodoform test.

5. **Testing Possible Options**:
- **Option B**: If we consider 3-pentanol (C₅H₁₁OH), hydrolysis could yield:
- B: CH₃-CHOH-CH₂-CH₂-CH₃ (3-pentanol)
- C: CH₃-CO-CH₃ (acetone)
Both of these can give a positive iodoform test.

- **Option C**: If we consider 2-pentanol (C₅H₁₁OH), hydrolysis could yield:
- B: CH₃-CO-CH₃ (acetone)
- C: CH₃-CHOH-CH₂-CH₃ (3-pentanol)
Again, both of these can give a positive iodoform test.

6. **Conclusion**:
Both options B and C yield products that can give a positive iodoform test. Therefore, compound (A) can be either 3-pentanol or 2-pentanol.

### Final Answer:
Compound (A) is either 3-pentanol or 2-pentanol, which upon hydrolysis gives compounds (B) and (C) that both give a positive iodoform test.