Oxidation state exhibited by Mn in `MnO_(2)` is

Answer

To determine the oxidation state of manganese (Mn) in manganese dioxide (MnO₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Oxidation States**:
- The oxidation state of oxygen (O) is typically -2.

2. **Write the Formula**:
- The chemical formula for manganese dioxide is MnO₂, which indicates there are two oxygen atoms.

3. **Set Up the Equation**:
- Let the oxidation state of manganese be represented as \( X \).
- Since there are two oxygen atoms, the total contribution from oxygen to the charge is \( 2 \times (-2) = -4 \).

4. **Apply the Neutrality Condition**:
- The compound MnO₂ is neutral overall, so the sum of the oxidation states must equal zero.
- Therefore, we can set up the equation:
\[ X + (-4) = 0 \]

5. **Solve for X**:
- Rearranging the equation gives:
\[ X - 4 = 0 \implies X = +4 \]

6. **Conclusion**:
- The oxidation state of manganese (Mn) in MnO₂ is +4.

### Final Answer:
The oxidation state exhibited by Mn in MnO₂ is +4.

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