Oxidation state exhibited by Fe in `Fe(CO)_(5)` is

Answer

To determine the oxidation state of iron (Fe) in the complex compound Fe(CO)₅, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Components of the Complex:**
- The complex is Fe(CO)₅, which consists of one iron atom and five carbon monoxide (CO) ligands.

2. **Understand the Nature of the Ligands:**
- CO (carbon monoxide) is a neutral ligand. This means that it does not contribute any charge to the overall oxidation state of the complex.

3. **Set Up the Equation:**
- Let the oxidation state of iron (Fe) be represented as \( X \).
- Since there are five CO ligands, the contribution from these ligands to the oxidation state is \( 0 \) (because they are neutral).
- The overall charge of the complex Fe(CO)₅ is neutral, which is \( 0 \).

4. **Write the Equation:**
- The equation can be set up as:
\[ X + (0 \times 5) = 0 \]
- Simplifying this gives:
\[ X + 0 = 0 \]
- Therefore:
\[ X = 0 \]

5. **Conclusion:**
- The oxidation state of iron (Fe) in Fe(CO)₅ is \( 0 \).

### Final Answer:
The oxidation state exhibited by Fe in Fe(CO)₅ is \( 0 \).