Write the products formed in the given reaction, also mention type of reaction:
`CH_(3)COOH+KOH rarr`

Answer

To solve the question, we need to identify the products formed when ethanoic acid (CH₃COOH) reacts with potassium hydroxide (KOH) and also classify the type of reaction.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in the reaction are ethanoic acid (CH₃COOH) and potassium hydroxide (KOH).

2. **Determine the Reaction Type**:
- Ethanoic acid is an acid, and potassium hydroxide is a base. When an acid reacts with a base, it typically undergoes a neutralization reaction.

3. **Write the Reaction**:
- The balanced chemical equation for the reaction is:
\[ \text{CH}_3\text{COOH} + \text{KOH} \rightarrow \text{CH}_3\text{COOK} + \text{H}_2\text{O} \]
- Here, potassium acetate (CH₃COOK) and water (H₂O) are formed.

4. **Identify the Products**:
- The products of the reaction are potassium acetate (CH₃COOK) and water (H₂O).

5. **Conclude the Type of Reaction**:
- Since this reaction involves an acid and a base producing a salt and water, it is classified as an acid-base reaction, also known as a neutralization reaction.

### Final Answer:
- **Products**: Potassium acetate (CH₃COOK) and water (H₂O)
- **Type of Reaction**: Acid-base reaction (Neutralization reaction)