Write the products formed in the given reaction, also mention type of reaction:
`HCOOH+KOH rarr`

Answer

To solve the problem, we need to identify the products formed when methanoic acid (HCOOH) reacts with potassium hydroxide (KOH) and classify the type of reaction.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are methanoic acid (HCOOH) and potassium hydroxide (KOH).

2. **Determine the Reaction Type**:
- Methanoic acid is an acid, and potassium hydroxide is a base. When an acid reacts with a base, it typically results in a neutralization reaction.

3. **Write the Balanced Chemical Equation**:
- The reaction can be represented as:
\[ \text{HCOOH} + \text{KOH} \rightarrow \text{HCOOK} + \text{H}_2\text{O} \]
- Here, potassium formate (HCOOK) is formed along with water (H2O).

4. **Identify the Products**:
- The products of the reaction are:
- Potassium formate (HCOOK)
- Water (H2O)

5. **Classify the Reaction**:
- Since the reaction involves an acid (HCOOH) reacting with a base (KOH) to produce a salt (HCOOK) and water (H2O), it is classified as a **neutralization reaction** or **acid-base reaction**.

### Final Answer:
- **Products**: Potassium formate (HCOOK) and Water (H2O)
- **Type of Reaction**: Neutralization reaction (Acid-Base reaction)