An isocyanide on reduction with hydrogen in the presence of platinum gives :

Options

A. amide
B. primary amine
C. secondary amine
D. alcohol

Answer

To solve the question regarding the reduction of an isocyanide with hydrogen in the presence of platinum, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Isocyanide**:
- An isocyanide (or isonitrile) has the general structure R-N≡C, where R is an alkyl or aryl group. For this example, we can consider a simple isocyanide like methyl isocyanide (CH3-N≡C).

2. **Understanding the Reduction Reaction**:
- The reduction of isocyanides typically involves the addition of hydrogen (H2) across the triple bond (N≡C) in the presence of a catalyst such as platinum (Pt). Platinum serves as a catalyst to facilitate the reaction.

3. **Mechanism of the Reaction**:
- When hydrogen gas is introduced, it dissociates into two hydrogen atoms. The nitrogen atom in the isocyanide has a lone pair of electrons and can act as a nucleophile.
- The nitrogen atom attacks one of the hydrogen atoms, leading to the formation of a bond between nitrogen and hydrogen. This results in the formation of an intermediate.

4. **Formation of the Amine**:
- As the reaction proceeds, the triple bond between carbon and nitrogen (N≡C) is reduced. The nitrogen now has a single bond with one hydrogen (NH) and the carbon is bonded to the alkyl group (R) and another hydrogen atom.
- The final product is a secondary amine, which can be represented as R-NH-R' where R' is the alkyl group from the isocyanide.

5. **Conclusion**:
- Therefore, the reduction of isocyanide with hydrogen in the presence of platinum yields a secondary amine.

### Final Answer:
The correct answer is **secondary amine**.