An organic compound "A" of molecular weight 120, gives Tollen's reagent test and 2,4-DNP test but no Iodoform with `I_(2)/OH^(Theta)` . The compound "A" may be

Options

A. Benzoic acid
B. Phenyl methyl ketone
C. 2-phenyl ethanal
D. 1-phenyl ethane

Explanation

To solve the problem, we need to identify the organic compound "A" based on the given information. Here’s a step-by-step breakdown of the reasoning:

### Step 1: Analyze the Tests
The compound "A" gives:
- **Tollen's Reagent Test**: This test is positive for aldehydes and some reducing sugars. It indicates that "A" is likely an aldehyde.
- **2,4-DNP Test**: This test is positive for both aldehydes and ketones, suggesting that "A" could be either.
- **No Iodoform Test**: The Iodoform test is positive for methyl ketones and certain alcohols (specifically, secondary alcohols with a methyl group adjacent to the hydroxyl group). The fact that "A" does not give a positive Iodoform test suggests it is not a methyl ketone or a secondary alcohol with a methyl group.

### Step 2: Assess Possible Structures
We need to consider the possible structures for "A" based on the tests and the molecular weight of 120 g/mol. The options provided are:
1. **Benzoic Acid**: This is a carboxylic acid and does not give a positive Tollen's test.
2. **Phenyl Methyl Ketone**: This would give a positive Iodoform test, so it can be ruled out.
3. **2-Phenyl Ethanol**: This is a secondary alcohol that does not have a methyl group adjacent to the hydroxyl group, so it would not give a positive Iodoform test.
4. **1-Phenyl Ethane**: This is an alkane and would not give a positive Tollen's or 2,4-DNP test.

### Step 3: Confirm the Correct Compound
Given the above analysis, the only compound that fits all the criteria (positive Tollen's and 2,4-DNP tests, negative Iodoform test, and a molecular weight of 120) is **2-Phenyl Ethanol**.

### Step 4: Calculate Molecular Weight
To confirm, we can calculate the molecular weight of 2-Phenyl Ethanol (C8H10O):
- Carbon (C): 8 × 12 = 96
- Hydrogen (H): 10 × 1 = 10
- Oxygen (O): 1 × 16 = 16

Total molecular weight = 96 + 10 + 16 = 122 g/mol.

### Conclusion
Thus, the compound "A" is **2-Phenyl Ethanol**.