Compound `P` Liberates `H_(2)` gas with `Na` metal. `P` gives the precipitate with tollen's reagent, there is no reponse towards Lucas reagent and compound `Q` gives instant turbidity with anhydrous `ZnCl_(2)//HCl_(1)` and with sodium metal `1` mole of compound `Q` liberates `11.2` litre `H_(2)` gas at `STP`. Find the structural formula of compound `P` and `Q`.

Options

A. P is `CH_(2)=CH-overset(O)overset(||)(C)-H`
B. Q is `CH_(3)-overset(CH_(3))overset(|)underset(OH)underset(|)(C)-CH_(2)-O-CH_(3)`
C. P is `CH_(3)-O-=C-H`
D. Q is `CH_(3)-overset(CH_(3))underset(|)underset(OH)underset(|)(C)-underset(OH)underset(|)(CH)-CH_(3)`

Answer

B, C

Explanation

`CH_(3)-O-C-=C-H` gives white precipitate with tollen's reagent liberates `H_(2)` gas with Na metal.
`CH_(3)-overset(CH_(3))overset(|)underset(OH)underset(|)(C)-CH_(2)-O-CH_(3)` gives turbidity with anhydrous `ZnCl_(2)//HCl` and liberates half mole `H_(2)` gas with sodium metal