Home
Class 11
CHEMISTRY
A solid having density of 9xx10^(3) kg ...

A solid having density of `9xx10^(3) kg m^(-3)` forms face centred cubic crystals of edge length `200sqrt2` pm . What is the molar mass of the solid? [Avogadro constant `approx 6 xx 10^23 mol^(-1) , pi approx 3 ` ]

A

`0.0432 kg mol^(-1)`

B

`0.0305 kg mol^(-1)`

C

`0.4320 kg mol^(-1)`

D

`0.0216 kg mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    RESONANCE ENGLISH|Exercise APSP|29 Videos

  • SOLID STATE

    RESONANCE ENGLISH|Exercise Part-II National standard examination in chemistry|27 Videos

  • SOLID STATE

    RESONANCE ENGLISH|Exercise Exercise -3 (Part-II)|18 Videos

  • S BLOCK ELEMENTS

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Biomolecules & Polymer)|4 Videos

  • STRUCTURAL IDENTIFICATION & PRACTICAL ORGANIC CHEMISTRY

    RESONANCE ENGLISH|Exercise Section -B|18 Videos

Similar Questions

Explore conceptually related problems

A solid having density of 9 xx 10^(3) kg m^(-3) forms face centred cubic crystals of edge length 200 sqrt2 pm. What is the molar mass of the solid ? [Avogadro constant ~= 6 xx 10^(23) mol^(-1), pi ~= 3 ]

A solid having density of 9 xx 10^(3) kg m^(-3) forms face centred cubic crystals of edge length 200 sqrt2 pm. What is the molar mass of the solid ? [Avogadro constant ~= 6 xx 10^(23) mol^(-1), pi ~= 3 ]

A substance has density of 2 kg dm^(-3) and it crystallizes to fcc lattice with edge length equal to 700 pm . The molar mass of the substance is _______ .

An element (at. mass = 60) having face centred cubic unit cell has a density of 6.23g cm^(-3) . What is the edge length of the unit cell? (Avogadro's constant = 6.023 xx 10^(23) mol^(-1) )

A substance has a face centred cubic crystal with a density 1.984 g cm^(-3) and edge length 630 pm. Calculate the molar mass of the substance

An element 'X' crystallises as face centred cubic lattice with edge length of 460 pm. The density of the element X, when molar mass of X atom is 60 g mol^(-1) is

A metal has an fcc latticed.The edge length of the unit cell is 404 pm .The density of the metal is 2.72 g//cm^(-3) .The molar mass of the metal is (N_(A) Avogadro's constant = 6.2 xx 10^(23) mol^(-1))

A body centred cubic element of density, 10.3 g cm^(-3) has a cell edge of 314 pm. Calculate the atomic mass of the element. ( N_A = 6.023 xx 10^(23) mol^(-1) )

An element with density 2.8 cm^(3) forms a f.c.c unit cell with edge length 4xx10^(-8) cm. calculate the molar mass of the element. Given: (N_(A)=6.022xx10^(23)) mol^(-1)