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The integral intcos(logex)dx is equal t...

The integral `intcos(log_ex)dx ` is equal to (where C is a contant of integration)

A

`x[cos(log_(e)x)-sin(log_(e)x)]+C`

B

`x/2[sin(log_(e)x)-cos(log_(e)x)]+C`

C

`x[cos(log_(e)x)+sin(log_(e)x)]+C`

D

`x/2[cos(log_(e)x)+sin(log_(e)x)]+C`

Text Solution

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