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The Certesian product AxxA has 16 elemen...

The Certesian product `AxxA` has 16 elements `S={(a,b)epsilonAxxA|altb}.(-1,2)` and `(0,1)` are two elements belonging to `S`. Find the set containing the remaining elements of `S`.

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To solve the problem, we need to find the remaining elements of the set \( S \) from the Cartesian product \( A \times A \) given the conditions. Let's break it down step by step. ### Step 1: Identify the elements of set \( A \) From the elements provided in set \( S \), we have: - The elements \( (-1, 2) \) and \( (0, 1) \) belong to \( S \). - The condition states that \( a < b \). From the pairs \( (-1, 2) \) and \( (0, 1) \), we can derive the elements of set \( A \): - The first element of the first pair is \( -1 \). - The second element of the first pair is \( 2 \). - The first element of the second pair is \( 0 \). - The second element of the second pair is \( 1 \). Thus, the set \( A \) can be identified as: \[ A = \{-1, 0, 1, 2\} \] ### Step 2: Determine the Cartesian product \( A \times A \) Next, we compute the Cartesian product \( A \times A \): \[ A \times A = \{(x, y) | x \in A, y \in A\} \] This results in the following pairs: - \( (-1, -1), (-1, 0), (-1, 1), (-1, 2) \) - \( (0, -1), (0, 0), (0, 1), (0, 2) \) - \( (1, -1), (1, 0), (1, 1), (1, 2) \) - \( (2, -1), (2, 0), (2, 1), (2, 2) \) ### Step 3: Filter the pairs based on the condition \( a < b \) Now, we filter these pairs to satisfy the condition \( a < b \): - From \( (-1, -1) \): Not included (not \( a < b \)) - From \( (-1, 0) \): Included - From \( (-1, 1) \): Included - From \( (-1, 2) \): Included - From \( (0, -1) \): Not included (not \( a < b \)) - From \( (0, 0) \): Not included (not \( a < b \)) - From \( (0, 1) \): Included - From \( (0, 2) \): Included - From \( (1, -1) \): Not included (not \( a < b \)) - From \( (1, 0) \): Not included (not \( a < b \)) - From \( (1, 1) \): Not included (not \( a < b \)) - From \( (1, 2) \): Included - From \( (2, -1) \): Not included (not \( a < b \)) - From \( (2, 0) \): Not included (not \( a < b \)) - From \( (2, 1) \): Not included (not \( a < b \)) - From \( (2, 2) \): Not included (not \( a < b \)) ### Step 4: Compile the remaining elements of set \( S \) The pairs that satisfy \( a < b \) are: - \( (-1, 0) \) - \( (-1, 1) \) - \( (-1, 2) \) - \( (0, 1) \) - \( (0, 2) \) - \( (1, 2) \) Now, we already know that \( (-1, 2) \) and \( (0, 1) \) are included in \( S \). Therefore, the remaining elements of set \( S \) are: \[ \{(-1, 0), (-1, 1), (0, 2), (1, 2)\} \] ### Final Answer The set containing the remaining elements of \( S \) is: \[ \{(-1, 0), (-1, 1), (0, 2), (1, 2)\} \]

To solve the problem, we need to find the remaining elements of the set \( S \) from the Cartesian product \( A \times A \) given the conditions. Let's break it down step by step. ### Step 1: Identify the elements of set \( A \) From the elements provided in set \( S \), we have: - The elements \( (-1, 2) \) and \( (0, 1) \) belong to \( S \). - The condition states that \( a < b \). ...
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