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Find the range of the following functio...

Find the range of the following functions: (where {.} and [.] represent fractional part and greatest integer part functions respectively)
`f(x)=[sinx+[cosx+[tanx+[secx]]]]` Here `xepsilon(0,pi//4)`

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To find the range of the function \( f(x) = [\sin x + [\cos x + [\tan x + [\sec x]]]] \) for \( x \in (0, \frac{\pi}{4}) \), we will analyze each component step by step. ### Step 1: Determine the ranges of the trigonometric functions 1. **Sine Function**: - As \( x \) approaches \( 0 \), \( \sin x \) approaches \( 0 \). - As \( x \) approaches \( \frac{\pi}{4} \), \( \sin x \) approaches \( \frac{\sqrt{2}}{2} \). - Therefore, \( \sin x \in (0, \frac{\sqrt{2}}{2}) \). 2. **Cosine Function**: - As \( x \) approaches \( 0 \), \( \cos x \) approaches \( 1 \). - As \( x \) approaches \( \frac{\pi}{4} \), \( \cos x \) approaches \( \frac{\sqrt{2}}{2} \). - Therefore, \( \cos x \in (\frac{\sqrt{2}}{2}, 1) \). 3. **Tangent Function**: - As \( x \) approaches \( 0 \), \( \tan x \) approaches \( 0 \). - As \( x \) approaches \( \frac{\pi}{4} \), \( \tan x \) approaches \( 1 \). - Therefore, \( \tan x \in (0, 1) \). 4. **Secant Function**: - As \( x \) approaches \( 0 \), \( \sec x \) approaches \( 1 \). - As \( x \) approaches \( \frac{\pi}{4} \), \( \sec x \) approaches \( \sqrt{2} \). - Therefore, \( \sec x \in (1, \sqrt{2}) \). ### Step 2: Apply the greatest integer function Now we will apply the greatest integer function (denoted as \( [x] \)) to each of these ranges. 1. **Greatest Integer of Sine**: - Since \( \sin x \in (0, \frac{\sqrt{2}}{2}) \), we have \( [\sin x] = 0 \) for all \( x \in (0, \frac{\pi}{4}) \). 2. **Greatest Integer of Cosine**: - Since \( \cos x \in (\frac{\sqrt{2}}{2}, 1) \), we have \( [\cos x] = 0 \) for all \( x \in (0, \frac{\pi}{4}) \). 3. **Greatest Integer of Tangent**: - Since \( \tan x \in (0, 1) \), we have \( [\tan x] = 0 \) for all \( x \in (0, \frac{\pi}{4}) \). 4. **Greatest Integer of Secant**: - Since \( \sec x \in (1, \sqrt{2}) \), we have \( [\sec x] = 1 \) for all \( x \in (0, \frac{\pi}{4}) \). ### Step 3: Combine the results Now we can substitute these values back into the original function: \[ f(x) = [\sin x + [\cos x + [\tan x + [\sec x]]]] \] Substituting the values we found: \[ f(x) = [0 + [0 + [0 + 1]]] \] Since \( [0 + 1] = 1 \), we have: \[ f(x) = [0 + [0 + 1]] = [0 + 1] = [1] = 1 \] ### Conclusion Thus, the range of the function \( f(x) \) for \( x \in (0, \frac{\pi}{4}) \) is: \[ \text{Range of } f(x) = \{1\} \]

To find the range of the function \( f(x) = [\sin x + [\cos x + [\tan x + [\sec x]]]] \) for \( x \in (0, \frac{\pi}{4}) \), we will analyze each component step by step. ### Step 1: Determine the ranges of the trigonometric functions 1. **Sine Function**: - As \( x \) approaches \( 0 \), \( \sin x \) approaches \( 0 \). - As \( x \) approaches \( \frac{\pi}{4} \), \( \sin x \) approaches \( \frac{\sqrt{2}}{2} \). - Therefore, \( \sin x \in (0, \frac{\sqrt{2}}{2}) \). ...
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