Write `R={(4x+3,1-x):xle2,xepsilonN}`

Explanation

To solve the problem, we need to write the relation \( R \) defined by the pairs \( (4x + 3, 1 - x) \) where \( x \) is a natural number and \( x \leq 2 \).

### Step-by-Step Solution:

1. **Identify the values of \( x \)**:
Since \( x \) is a natural number and \( x \leq 2 \), the possible values for \( x \) are:
\[ x = 1, 2 \]

2. **Calculate the pairs for each value of \( x \)**:
- For \( x = 1 \):
\[ (4x + 3, 1 - x) = (4(1) + 3, 1 - 1) = (4 + 3, 0) = (7, 0) \]
- For \( x = 2 \):
\[ (4x + 3, 1 - x) = (4(2) + 3, 1 - 2) = (8 + 3, -1) = (11, -1) \]

3. **Write the relation \( R \)**:
Now, we can compile the pairs we calculated:
\[ R = \{(7, 0), (11, -1)\} \]

### Final Answer:
The relation \( R \) is:
\[ R = \{(7, 0), (11, -1)\} \]