An `AC` voltage source `V=200sqrt2 sin 100t` is connected across a circuit containing an `AC` ammeter (it reads `rms` value )and capacitor of capacity `1 muF`.The reading of ammeter is:

Explanation

Comparing `E=200sqrt2 sin (100t) with E=E_(0) sin omega t ` we find that.
`E_(0) =200sqrt2V and omega=100(rad//s)`
`"So", X_(C)=(1)/(omegaC)=(1)/(100xx10^(-6))=10^(4)Omega`
And as ac instruments reads rms value. The readin of ammeter will be,
`I_("rms")=(E_(rms))/(X_(c))=(E_(0))/(sqrt2X_(c))["as" E_(rms)=(E_(0))/(sqrt2)]`
`i.e. I_(rms)=(200sqrt2)/(sqrt2xx10^(4))=200mA`