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In the circuit diagram show, X(C)=100 Om...

In the circuit diagram show, `X_(C)=100 Omega, X_(L)=200Omega and R=100 Omega`. The effective current through the source is

A

2A

B

`2sqrt2A`

C

0.5A

D

`sqrt0.4A`

Text Solution

Verified by Experts

`"In"=(V)/(R)=(200)/(100)=2A`
`I'=(V)/(X_(L)-X_(C))=(200)/(100)=2A`
`I=sqrt(1_(R)^(2)+I^(2))=2sqrt2"Amp"`
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