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Two cells of unequal emfs epsi(1)" and "...

Two cells of unequal emfs `epsi_(1)" and "epsi_(2)`, and internal resistances `r_(1)" and "r_(2)` are joined as shown. `V_(A)" and "V_(B)` are the potentials as A and B respectively.

A

One cell will supply energy to the other

B

The potential difference across both the cells will be equal

C

The potential difference across one cell will be greater then its emf

D

`V_(A)-V_(B)=((epsi_(1)r_(2)+epsi_(2)r_(1)))/(r_(1)+r_(2))`

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The correct Answer is:
A, B, C, D
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RESONANCE ENGLISH-CURRENT ELECTRICITY-Exercise-2 (Part-3)
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  4. Consider a cylindrical conductor of length L and area of cross - secti...

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  5. N cells each of e.m.f. E & internal resistance r are grouped into sets...

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  6. In the circuit shown in fig. the cell has emf 10V and internal resista...

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  7. In the network shown, points A, B and C have potentials of 70 V, zero ...

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  8. In the circuit shown in figure

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  9. A battery of emf E and internal resistance r is connected across a res...

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  10. Potential difference across the terminal of a non ideal battery is

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  11. A cell of emf epsilon and internal resistance r drives a current i thr...

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  12. In the given figure, E=12V, R(1)=3Omega, R(2)=2Omega" and "r=1Omega. T...

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  15. A microammeter has as resistance of 100 Omega and full scale range of ...

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  16. Two cells of unequal emfs epsi(1)" and "epsi(2), and internal resistan...

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  17. Three voltmeters all having different resistance, are joined as shown....

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  18. In the potentiometer arrangement shown, the driving cell A has emf eps...

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  20. Which of the following statement is/are correct?

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