If `V=x^(2)y+y^(2)z` then find `vec(E)` at (x, y, z)

Explanation

To find the electric field \(\vec{E}\) from the given potential \(V = x^2y + y^2z\), we will use the relationship between electric field and electric potential. The electric field is given by:

\[ \vec{E} = -\nabla V \]

where \(\nabla V\) is the gradient of the potential \(V\).

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