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Two point charges of same magnitude and opposite sign are fixed at point a and B. A third small point charge is to be balanced at point P by the electrostatic force due to these two charges. The point P :

A

lies on the perpendicular bisector of line AB

B

is at mid point of line AB

C

lies to the left of A

D

none of these

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The correct Answer is:
D
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RESONANCE ENGLISH-ELECTROSTATICS-Exercise - 2 Part - I
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