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Find the distance of a point from the ea...

Find the distance of a point from the earth's centre where the resultant gravitational field due to the earth and the moon is zero The mass of the earth is `6.0 xx 10^(24)kg` and that of the moon is `7.4 xx 10^(22)kg` The distance between the earth and the moon is `4.0 xx 10^(5)km` .

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To find the distance of a point from the Earth's center where the resultant gravitational field due to the Earth and the Moon is zero, we can follow these steps: ### Step 1: Define the Variables Let: - \( M_e = 6.0 \times 10^{24} \, \text{kg} \) (mass of the Earth) - \( M_m = 7.4 \times 10^{22} \, \text{kg} \) (mass of the Moon) - \( d = 4.0 \times 10^{5} \, \text{km} = 4.0 \times 10^{8} \, \text{m} \) (distance between the Earth and the Moon) - \( x \) = distance from the center of the Earth to the point where the gravitational fields cancel out. ...
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Find the distance of a point from the earth's centre where the resultant gravitational field due to the earth and the moon is zero. The mass of the earth is 6.0xx10^24 kg and that of the moon is 7.4x10^22 kg. The distance between the earth and the moon is 4.0xx10^5km .

What is the magnitude of the gravitational force between the Earth and a 1kg object on its surface ? (Mass of the earth is 6xx10^(24) kg and radius of the Earth is 6.4xx10^(6) m) .

Calculate the distance from the earth to the point where the gravitational field due to the earth and the moon cancel out. Given that the earth-moon distance is 3.8 xx 10^(8) m and the mass of earth is 81 times that of moon.

Calculate the force of gravitation between the earth the sun, given that the mass of the earth =6xx10^(24) kg and mass of the sun =2xx10^(30) kg. The average distance between the two is 1.5xx10^(11)m .

Find the ratio of escape velocities from the earth and the moon. (Mass of the earth = 6.0 xx 10^(24) kg , Radius of the earth = 6400 km, Mass of the moon = 7.4 xx 10^(22) kg Radius of the moon = 1740 km.)

The mass of the earth is 6xx10^(24)kg and that of the moon is 7.4xx10^(22)kg . The potential energy of the system is -7.79xx10^(28)J . The mean distance between the earth and moon is (G=6.67xx10^(-11)Nm^(2)kg^(-2))

Find the gravitational due to the moon at its surface. The mass of the moon is 7.36xx10^2 klg and the radius of the moon is 1.74xx10^m . Assuming the moon be a spherically symmetric body

Calculate the escape velocity from the moon. The mass of the moon =7.4xx10^22kg and radius of the moon =1740km

Calculate the escape velocity from the moon. The mass of the moon =7.4xx10^22kg and radius of the moon =1740km

The mass of the earth is 6 × 10^(24) kg and that of the moon is 7.4 xx 10^(22) kg. If the distance between the earth and the moon is 3.84xx10^(5) km, calculate the force exerted by the earth on the moon. (Take G = 6.7 xx 10^(–11) N m^(2) kg^(-2) )

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