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Let A,B,C,D be real matrices such that A...

Let A,B,C,D be real matrices such that `A^(T)=BCD,B^(T)=CDA,C^(T)=DAB and D^(T)=ABC` for the matrix M=ABCD then find `M^(3)`?

A

M

B

`M^(2)`

C

`M^(3)`

D

`M^(4)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find \( M^3 \) for the matrix \( M = ABCD \) given the relationships between the matrices \( A, B, C, \) and \( D \). ### Step-by-Step Solution: 1. **Understanding the Transpose Relationships**: We are given the following relationships: - \( A^T = BCD \) - \( B^T = CDA \) - \( C^T = DAB \) - \( D^T = ABC \) 2. **Finding the Transpose of \( M \)**: We start with the matrix \( M \): \[ M = ABCD \] To find \( M^T \), we use the property of transposes: \[ M^T = (ABCD)^T = D^T C^T B^T A^T \] 3. **Substituting the Transpose Relationships**: Now we substitute the transpose relationships into the equation: - Substitute \( D^T = ABC \) - Substitute \( C^T = DAB \) - Substitute \( B^T = CDA \) - Substitute \( A^T = BCD \) Thus, we have: \[ M^T = (ABC)(DAB)(CDA)(BCD) \] 4. **Rearranging the Terms**: Now we can rearrange the terms: \[ M^T = ABCD \cdot ABCD \cdot ABCD = M \cdot M \cdot M = M^3 \] 5. **Conclusion**: From the above steps, we find that: \[ M^T = M^3 \] This means that \( M^3 \) is equal to the transpose of \( M \). ### Final Result: Thus, we conclude that: \[ M^3 = M^T \]
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RESONANCE ENGLISH-MATRICES & DETERMINANT-PART-III
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  6. " if " Delta = |{:(-x,,a,,b),(b,,-x,,a),(a,,b,,-x):}|" then a fac...

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  9. If a non-singular matrix and A^(T) denotes the tranpose of A, then

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  10. Let "Let"(x)=|{:(,2sinx,sin^(2)x,0),(,1,2sin x,sin^(2)x),(,0,1,2sin x)...

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  11. Let Delta=|{:(,1,x,x^(2)),(,x^(2),1,x),(,x,x^(2),1):}|. Then

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  12. Let f(x)=|{:(,1//x,logx,x^(n)),(,1,-1//n,(-1)^(n)),(,1,a,a^(2)):}| whe...

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  13. If D is determinant of order three of Delta is a determinant formed by...

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  14. Let A,B,C,D be real matrices such that A^(T)=BCD,B^(T)=CDA,C^(T)=DAB a...

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