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Aqueous solution of nickel sulphate on t...

Aqueous solution of nickel sulphate on treating with pyridine and then adding a solution of sodium nitrite gives dark blue crystals of :

A

`[Ni(py)_(4)]SO_(4)`

B

`[Ni(py)_(2)(NO_(2))_(2)]`

C

`[Ni(py)_(4)](NO_(2))_(2)`

D

`[Ni(py)_(3)(NO_(2))]_(2)SO_(4)`

Text Solution

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The correct Answer is:
To solve the question, we need to analyze the reaction that occurs when an aqueous solution of nickel sulfate is treated with pyridine and then sodium nitrite. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the reactants The first reactant is nickel sulfate, which in aqueous solution can be represented as NiSO₄·6H₂O (hydrated form). The second reactant is pyridine (C₅H₅N), which is a strong field ligand. **Hint:** Look for the chemical formula of nickel sulfate and understand its hydrated form. ### Step 2: Understand the role of pyridine Pyridine is a stronger field ligand compared to water (H₂O). In coordination chemistry, stronger ligands can displace weaker ligands from the coordination sphere of the metal ion. Here, pyridine will displace the water molecules coordinated to nickel. **Hint:** Recall the spectrochemical series to determine the strength of ligands. ### Step 3: Formation of the complex When pyridine displaces water, it forms a complex with nickel. The complex formed can be represented as [Ni(C₅H₅N)₄]²⁺. In this complex, four pyridine molecules coordinate to the nickel ion. **Hint:** Consider how many pyridine molecules are needed to replace the water molecules around the nickel ion. ### Step 4: Addition of sodium nitrite After forming the nickel-pyridine complex, sodium nitrite (NaNO₂) is added. The nitrite ions can act as counter ions in the complex, leading to the formation of [Ni(C₅H₅N)₄](NO₂)₂. **Hint:** Think about how counter ions balance the charge of the complex ion formed. ### Step 5: Color of the complex The resulting complex [Ni(C₅H₅N)₄](NO₂)₂ is known to exhibit a dark blue color. This is characteristic of certain nickel complexes, especially those with strong field ligands like pyridine. **Hint:** Remember that the color of coordination compounds can often indicate the type of ligands and the oxidation state of the metal. ### Conclusion Thus, the dark blue crystals formed from the reaction of aqueous nickel sulfate with pyridine and sodium nitrite are [Ni(C₅H₅N)₄](NO₂)₂. ### Final Answer The dark blue crystals formed are [Ni(C₅H₅N)₄](NO₂)₂.

To solve the question, we need to analyze the reaction that occurs when an aqueous solution of nickel sulfate is treated with pyridine and then sodium nitrite. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the reactants The first reactant is nickel sulfate, which in aqueous solution can be represented as NiSO₄·6H₂O (hydrated form). The second reactant is pyridine (C₅H₅N), which is a strong field ligand. **Hint:** Look for the chemical formula of nickel sulfate and understand its hydrated form. ### Step 2: Understand the role of pyridine ...
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