Home
Class 12
CHEMISTRY
For KMnO(4) in neutral medium correct co...


For `KMnO_(4)` in neutral medium correct combination is -

A

(I) (iii) (Q)

B

(II) (i) (R)

C

(I) (iii) (S)

D

(II) (iii) (R)

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE ENGLISH|Exercise Exercise -3 (Part-I)|5 Videos

  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE ENGLISH|Exercise Exercise -3 (Part-II)|7 Videos

  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE ENGLISH|Exercise Exercise -2 (Part-III)|5 Videos

  • ELECTROCHEMISRY

    RESONANCE ENGLISH|Exercise Advanced Level Problems|88 Videos

  • FUNDAMENTAL CONCEPT

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Fundamental Concept )|40 Videos

Similar Questions

Explore conceptually related problems

n-Factor of KMnO_(4) in neutral medium is

1 mole of equimolar mixture of ferric oxalate and ferrous oxalate requres x mole of KMnO_(4) in acidic medium for complete oxidation. X is:

1 mole of equimolar mixture of Fe_(2)(C_(2)O_(4))_(3) and FeC_(2)O_(4) required X moles of KMnO_(4) in acid medium for complete reaction. The value of X is:

Volumetric titrations involving KMnO_(4) , are carried out only in presence of dilute H_(2)SO_(4) but not in the presence of HCI or HNO_(3) This is because oxygen produced from KMnO_(4) + dil: H_(2)SO_(4) , is used only for oxidizing the reducing agent. Moreover, H2SO4 does not give any oxygen of its own to oxidize the reducing agent. In case HCI is used, the oxygen produced from KMnO_(4) + HCI is partly used up to oxidize HCI and in case HNO_(3) is used, it itself acts as oxidizing agent and partly oxidizes the reducing agent. KMnO_(4) , in various mediums gives following products Mn^(7+)overset(H^(+))toMn^(2+) Mn^(7+)overset(H_(2)O)toMn^(4+) Mn^(7+)underset(OH^(-))toMn^(6+) Q MnO_(4)^(2-) (1 mole) in neutral medium disproportionates to,

Reaction of KMnO_(4) in neutral or very weakly alkaline solution can be represented as:

Molecular weight of KMnO_(4) in acidic medium and neutral medium will be respecitvely -

The equivalent mass of KMnO_4 in alkaline and neutral mediums is ul"one-fifth" of its molecular mass.

An equal volume of reducing agent is titrated separately with 1 M KMnO_(4) in acid, neutral and alkaline medium. The volumes of KMnO_(4) required are 20 mL, 33.3 mL and 100 mL in acid, neutral and alkaline medium respectively. Find out oxidation state of Mn in each reaction product. Give balance equation. Find the volume of 1 M K_(2)Cr_(2)O_(7) consumed if same volume of reductant is titrated in acid medium.

STATEMENT-1: Equivalent mass of KMnO_(4) in different mediums are different STATEMENT-2 KMnO_(4) can act as a oxidising agent .

When KMnO_(4) reacts with KBr in acidic medium then oxidation state of Mn changes from +7 to :-