Chlorine on reaction with hot and concentrated sodium hydroxide gives:

Options

A. `ClO_3^-` and `ClO_2^-`
B. `Cl^-` and `ClO^-`
C. `Cl^-` and `ClO_3^-`
D. `Cl^-` and `ClO_2^-`

Answer

To solve the question regarding the reaction of chlorine with hot and concentrated sodium hydroxide, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are chlorine (Cl₂) and sodium hydroxide (NaOH). The sodium hydroxide is specifically hot and concentrated.

2. **Understand the Reaction Conditions**:
- The reaction occurs under hot and concentrated conditions, which indicates that the reaction will proceed more vigorously and may lead to the formation of different products compared to a reaction at room temperature or dilute conditions.

3. **Write the Reaction**:
- When chlorine reacts with hot and concentrated sodium hydroxide, it undergoes a disproportionation reaction. Chlorine is both oxidized and reduced in this process.
- The balanced chemical equation for the reaction is:
\[ 3 \text{Cl}_2 + 6 \text{NaOH} \rightarrow 5 \text{NaCl} + \text{NaClO}_3 + 3 \text{H}_2\text{O} \]
- In this reaction, chlorine (Cl₂) is converted into chloride ions (Cl⁻) and chlorate ions (ClO₃⁻).

4. **Identify the Products**:
- From the balanced equation, we can see that the products formed are:
- Sodium chloride (NaCl) which dissociates into Cl⁻ ions.
- Sodium chlorate (NaClO₃) which contains ClO₃⁻ ions.
- Water (H₂O).

5. **Conclusion**:
- Therefore, when chlorine reacts with hot and concentrated sodium hydroxide, it produces chloride ions (Cl⁻), chlorate ions (ClO₃⁻), and water (H₂O). The correct answer to the question is that chlorine gives both Cl⁻ and ClO₃⁻ ions.

### Final Answer:
- The products of the reaction are Cl⁻ (chloride ion) and ClO₃⁻ (chlorate ion).