Which of the following compound can not show geometrical isomerism?1

Options

A.
B.
C.
D.

Answer

To determine which compound cannot show geometrical isomerism, we need to understand the concept of geometrical isomerism and analyze the given options. Here’s a step-by-step solution:

### Step 1: Understand Geometrical Isomerism
Geometrical isomerism occurs in compounds that have the same molecular formula but differ in the spatial arrangement of atoms or groups around a double bond or a ring structure. For geometrical isomerism to occur, the compound must have:
- A carbon-carbon double bond (C=C) or a cyclic structure.
- Different groups attached to the carbons involved in the double bond or ring.

### Step 2: Analyze Each Option
Let’s analyze the options provided to see which one cannot show geometrical isomerism.

1. **Option A**: The compound has identical groups attached to the same carbon atom (e.g., two bromine atoms on one carbon). Since there are no different groups attached, this compound cannot show geometrical isomerism.

2. **Option B**: This compound has different groups attached to the carbons involved in the double bond. Therefore, it can show geometrical isomerism.

3. **Option C**: Similar to option B, this compound has different groups attached to the carbons, allowing for geometrical isomerism.

4. **Option D**: This compound also has different groups attached to the carbons, which means it can show geometrical isomerism.

### Step 3: Conclusion
After analyzing all the options, we find that:
- **Option A** is the compound that cannot show geometrical isomerism because it has identical groups attached to the same carbon, preventing any spatial arrangement differences.

### Final Answer
The compound that cannot show geometrical isomerism is **Option A**.

---