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Which number is larger (1.01)^(1000000) ...

Which number is larger `(1.01)^(1000000) or 10,000` ?

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To determine which number is larger between \( (1.01)^{1000000} \) and \( 10,000 \), we can use the properties of exponents and logarithms. Here’s a step-by-step solution: ### Step 1: Rewrite the comparison We need to compare \( (1.01)^{1000000} \) and \( 10,000 \). To make the comparison easier, we can take the logarithm of both sides. ### Step 2: Take the logarithm Taking the natural logarithm (or logarithm base 10) of both sides, we have: \[ \log((1.01)^{1000000}) \quad \text{and} \quad \log(10,000) \] ### Step 3: Simplify using logarithm properties Using the power rule of logarithms, we can simplify the left side: \[ \log((1.01)^{1000000}) = 1000000 \cdot \log(1.01) \] For the right side: \[ \log(10,000) = \log(10^4) = 4 \] ### Step 4: Compare the two logarithmic expressions Now we need to compare: \[ 1000000 \cdot \log(1.01) \quad \text{and} \quad 4 \] ### Step 5: Calculate \( \log(1.01) \) Using a calculator or logarithm table, we find: \[ \log(1.01) \approx 0.004321 \] ### Step 6: Calculate \( 1000000 \cdot \log(1.01) \) Now we can calculate: \[ 1000000 \cdot \log(1.01) \approx 1000000 \cdot 0.004321 = 4321 \] ### Step 7: Compare the results Now we compare: \[ 4321 \quad \text{and} \quad 4 \] Since \( 4321 > 4 \), we conclude that: \[ 1000000 \cdot \log(1.01) > 4 \] ### Conclusion Thus, we find that: \[ (1.01)^{1000000} > 10,000 \] ### Final Answer Therefore, \( (1.01)^{1000000} \) is larger than \( 10,000 \). ---
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