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There are fifteen players for a cricket ...

There are fifteen players for a cricket match
In how many ways the 11 players can be selected including a particular player?

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To solve the problem of selecting 11 players from a group of 15, including a particular player, we can follow these steps: ### Step 1: Understand the Problem We have 15 players, and we need to select 11 players for a cricket match. One of these players is a particular player (let's call this player P1) who must be included in the selection. ### Step 2: Fix the Particular Player Since P1 is already included in the team, we only need to select 10 more players from the remaining players. ### Step 3: Determine the Remaining Players After including P1, we have 14 players left (P2, P3, ..., P15) from which we need to select the remaining 10 players. ### Step 4: Use Combinations to Select the Players The number of ways to choose 10 players from 14 can be calculated using combinations. The formula for combinations is given by: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] In our case, we need to calculate: \[ \binom{14}{10} \] ### Step 5: Simplify the Combination Using the combination formula, we have: \[ \binom{14}{10} = \frac{14!}{10!(14-10)!} = \frac{14!}{10! \cdot 4!} \] ### Step 6: Expand the Factorials We can simplify this further. We know that: \[ 14! = 14 \times 13 \times 12 \times 11 \times 10! \] Thus, we can write: \[ \binom{14}{10} = \frac{14 \times 13 \times 12 \times 11 \times 10!}{10! \cdot 4!} \] ### Step 7: Cancel Out the Factorials The \(10!\) in the numerator and denominator cancels out: \[ \binom{14}{10} = \frac{14 \times 13 \times 12 \times 11}{4!} \] ### Step 8: Calculate \(4!\) We know that: \[ 4! = 4 \times 3 \times 2 \times 1 = 24 \] ### Step 9: Substitute and Calculate Now substituting back, we have: \[ \binom{14}{10} = \frac{14 \times 13 \times 12 \times 11}{24} \] Calculating the numerator: \[ 14 \times 13 = 182 \] \[ 182 \times 12 = 2184 \] \[ 2184 \times 11 = 24024 \] Now, divide by 24: \[ \frac{24024}{24} = 1001 \] ### Final Answer Thus, the number of ways to select 11 players including the particular player is: \[ \boxed{1001} \] ---
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