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At a party, each man danced with exactly...

At a party, each man danced with exactly four women and each woman danced with exactly three men. Nine men attended the party. How many women attended the party?

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To solve the problem step by step, we can follow these calculations: 1. **Identify the number of men and their dancing partners**: - We know that there are 9 men at the party. - Each man danced with exactly 4 women. 2. **Calculate the total number of dance pairs**: - The total number of dance pairs can be calculated by multiplying the number of men by the number of women each man danced with. - Total dance pairs = Number of men × Number of women each man danced with = 9 men × 4 women = 36 dance pairs. 3. **Set up the relationship for women**: - Let the number of women be denoted as \( w \). - Each woman danced with exactly 3 men. - Therefore, the total number of dance pairs can also be expressed as the number of women multiplied by the number of men each woman danced with. - Total dance pairs = Number of women × Number of men each woman danced with = \( w \times 3 \). 4. **Set the equations equal to each other**: - Since both expressions represent the total number of dance pairs, we can set them equal to each other: \[ 3w = 36 \] 5. **Solve for \( w \)**: - To find the number of women, divide both sides of the equation by 3: \[ w = \frac{36}{3} = 12 \] 6. **Conclusion**: - Therefore, the number of women who attended the party is \( 12 \).
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