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The 7th term of a H.P. is (1)/(10) and 1...

The 7th term of a H.P. is `(1)/(10)` and 12 th term is `(1)/(25),` find the 20th term of H.P.

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To find the 20th term of the given Harmonic Progression (H.P.), we will follow these steps: ### Step 1: Understand the relationship between H.P. and A.P. The terms of a Harmonic Progression can be expressed as the reciprocals of the terms of an Arithmetic Progression (A.P.). If the terms of the H.P. are \( T_n \), then the corresponding terms of the A.P. can be denoted as \( A_n \). ### Step 2: Write down the given terms We know: - The 7th term of the H.P. is \( T_7 = \frac{1}{10} \) - The 12th term of the H.P. is \( T_{12} = \frac{1}{25} \) ### Step 3: Find the corresponding terms in A.P. The corresponding terms in the A.P. would be: - \( A_7 = \frac{1}{T_7} = 10 \) - \( A_{12} = \frac{1}{T_{12}} = 25 \) ### Step 4: Write the general term of the A.P. The general term of an A.P. can be expressed as: \[ A_n = A + (n-1)D \] where \( A \) is the first term and \( D \) is the common difference. ### Step 5: Set up equations for the given terms From the information we have: 1. For the 7th term: \[ A + 6D = 10 \quad \text{(1)} \] 2. For the 12th term: \[ A + 11D = 25 \quad \text{(2)} \] ### Step 6: Solve the equations Subtract equation (1) from equation (2): \[ (A + 11D) - (A + 6D) = 25 - 10 \] This simplifies to: \[ 5D = 15 \] Thus, we find: \[ D = 3 \] ### Step 7: Substitute \( D \) back to find \( A \) Substituting \( D = 3 \) back into equation (1): \[ A + 6(3) = 10 \] \[ A + 18 = 10 \] \[ A = 10 - 18 = -8 \] ### Step 8: Find the 20th term of the A.P. Now we can find the 20th term of the A.P. using: \[ A_{20} = A + 19D \] Substituting \( A = -8 \) and \( D = 3 \): \[ A_{20} = -8 + 19(3) = -8 + 57 = 49 \] ### Step 9: Find the 20th term of the H.P. The 20th term of the H.P. is the reciprocal of the 20th term of the A.P.: \[ T_{20} = \frac{1}{A_{20}} = \frac{1}{49} \] ### Final Answer: The 20th term of the H.P. is \( \frac{1}{49} \). ---
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