To find the value of int(1+logx)/(x)dx, ...

To find the value of `int(1+logx)/(x)dx`, the proper substitution is

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int (1)/(x) dx = ..........+c
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int (1)/( x ^(2) - a ^(2)) dx =.....................+c
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int (7x + 9) ^(13) dx = ........................+c
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int e ^(4x -3) dx = .....................+c
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int 5 ^( 6x +9) dx = .......................+c
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int (5 ( x ^(6) + 1))/( x ^(2) +1 ) =.........................+c
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int (x ^(2) + x-6)/((x -2) (x -1))dx = x + ...................+ c
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If f ' (x) = (1)/(x) + x and f (1) = (5)/(2) then f (x) = log x + (x ...
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To find the value of int(1+logx)/(x)dx, the proper substitution is
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int (1)/(x ^(3)) [log x ^(x) ] ^(2) dx = p (log x ) ^(3) + c Then p = ...
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