The relation 3t=sqrt(3x)+6 describes the displacement of a particle in one" direction where "x" is in metres and t in sec.The displacement,when velocity is zero,is meters.

The relation 3t=sqrt(3x)+6 describe the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero is

The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

If the displacement of a particle varies with time as sqrt x = t+ 3

The displacement of a partcle is given by x=(t-2)^(2) where x is in metre and t in second. The distance coverred by the particle in first 3 seconds is

For a particle displacement time relation is t = sqrt(x) + 3 . Its displacement when its velocity is zero -

The displacement of a particle in S.H.M. is given by x = sinomegat+sqrt(3)cosomegatm . Then at t = 0 its displacement in metres is

Displacement x of a particle varies with time as sqrt(x)=t+5 , where x is in metres and time t is in seconds, Select the correct option.

The displacement of a particle is given by y= 5 xx 10 ^(-4) sin (100 t-50 x) , where x is in meter and t in sec, find out the velocity of the wave

The displacement x of particle moving in one dimension, under the action of a constant force is related to the time t by the equation t = sqrt(x) +3 where x is in meters and t in seconds . Find (i) The displacement of the particle when its velocity is zero , and (ii) The work done by the force in the first 6 seconds .

The distance x of a particle moving in one dimensions, under the action of a constant force is related to time t by the equation, t=sqrt(x)+3 , where x is in metres and t in seconds. Find the displacement of the particle when its velocity is zero.