Home
Class 12
PHYSICS
A particle is executing simple harmonic ...

A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential Energy (PE) equals kinetic energy (KE), the position of the particle will be :

A

`A/(sqrt2)`

B

`A/(2sqrt2)`

C

A

D

`A/2`

Text Solution

Verified by Experts

The correct Answer is:
A

KE = PE
`1/2 mV^2 = 1/2 kx^2 implies 1/2 m omega^2 (A^2 - x^2) = 1/2 m omega^2 x^2`
`A^2 - x^2 = x^2 implies x = A/(sqrt(2))`
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST - 1 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS - SECTION 2|5 Videos
  • JEE MAIN REVISION TEST - 30 | JEE -2020

    VMC MODULES ENGLISH|Exercise PHYSICS|25 Videos
  • JEE MAIN REVISION TEST - 1 | JEE - 2020

    VMC MODULES ENGLISH|Exercise PHYSICS ( SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

A particle is executing simple harmonic motion. Its total energy is proportional to its

A particle executes simple harmonic motion of amplitude A along the x - axis. At t = 0 , the position of the particle is x = (A)/(2) and it moves along the positive x - direction. Find the phase constant delta , if of the equation is written as x = Asin (omega t + delta) .

A particle executes simple harmonic motion of amplitude A along the X-axis. At t=0 the position of the particle is x=A/2 and it moves along the positive x-direction. Find the phase constant delta if the equation is written as x=Asin(omegat+delta)

A particle executing simple harmonic motion with an amplitude A. The distance travelled by the particle in one time period is

A particle is executing simple harmonic motion with a time period T . At time t=0, it is at its position of equilibium. The kinetice energy -time graph of the particle will look like

A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal?

A particle is executing simple harmonic motion with an amplitude A and time period T. The displacement of the particles after 2T period from its initial position is

The particle executing simple harmonic motion has a kinetic energy K_(0) cos^(2) omega t . The maximum values of the potential energy and the energy are respectively

A particle executing simple harmonic motion with time period T. the time period with which its kinetic energy oscillates is

The differential equation of a particle executing simple harmonic motion along y-axis is